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16x^2=49x^2
We move all terms to the left:
16x^2-(49x^2)=0
We add all the numbers together, and all the variables
-33x^2=0
a = -33; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-33)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{-66}=0$
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